Maths question?

May be...

3y= 3+75/19



3y= 132/19



y= 44/19



How did 3y= 3+75/19 become 132/19



how did they calculate it? What do i have to do to get 132/19



Help plz .. tried and couldn't get it

ROXXY! DON'T WORRY DEAR

MAIN HOON NA

look! 3+75/19(here we are adding two rational no.s i.e.,3 &75/19

their denominators are 1&19(we can write 3 as 3/1)

now we will take L.C.M. of denominators=19

now divide lcm ie, 19 by 1(denom. of 1st fraction ie,3/1)we will get 19, multiply result by numer. of same fraction ,we'll get19*3=57

so, fraction w'll be 57/19

similarly,when den. of 2nd frction'll b divided byl.c.m ,result'll b 1 so,1*75=17

2nd fraction 'll become75/19

now u can simply add them ,like this

57/19+75/19=(57+75)/19

=132/19

ur problem is solved

Because a common denominator of 19 was made.



3 + 75/19

= 3*(19/19) + 75/19

= (3*19)/19 + 75/19

= 57/19 + 75/19

= (57 + 75) / 19

= 132/19

3y = 3 + 75/19

3y = (3/1 * 19/19) + 75/19

3y = 57/19 + 75/19

3y = 132/19

y = (132/19)/(3/1)

y = 132/19 * 1/3

y = 132/57

y = (132/3)/(57/3)

y = 44/19

y = 2 6/19

3y = (57 + 75)/19

57y = 132

y = 132/57